3.2776 \(\int \frac {(c x)^n}{a+b x^n} \, dx\)

Optimal. Leaf size=40 \[ \frac {(c x)^{n+1} \, _2F_1\left (1,1+\frac {1}{n};2+\frac {1}{n};-\frac {b x^n}{a}\right )}{a c (n+1)} \]

[Out]

(c*x)^(1+n)*hypergeom([1, 1+1/n],[2+1/n],-b*x^n/a)/a/c/(1+n)

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Rubi [A]  time = 0.01, antiderivative size = 40, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.067, Rules used = {364} \[ \frac {(c x)^{n+1} \, _2F_1\left (1,1+\frac {1}{n};2+\frac {1}{n};-\frac {b x^n}{a}\right )}{a c (n+1)} \]

Antiderivative was successfully verified.

[In]

Int[(c*x)^n/(a + b*x^n),x]

[Out]

((c*x)^(1 + n)*Hypergeometric2F1[1, 1 + n^(-1), 2 + n^(-1), -((b*x^n)/a)])/(a*c*(1 + n))

Rule 364

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(a^p*(c*x)^(m + 1)*Hypergeometric2F1[-
p, (m + 1)/n, (m + 1)/n + 1, -((b*x^n)/a)])/(c*(m + 1)), x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[p, 0] &&
 (ILtQ[p, 0] || GtQ[a, 0])

Rubi steps

\begin {align*} \int \frac {(c x)^n}{a+b x^n} \, dx &=\frac {(c x)^{1+n} \, _2F_1\left (1,1+\frac {1}{n};2+\frac {1}{n};-\frac {b x^n}{a}\right )}{a c (1+n)}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 36, normalized size = 0.90 \[ \frac {x (c x)^n \, _2F_1\left (1,1+\frac {1}{n};2+\frac {1}{n};-\frac {b x^n}{a}\right )}{a (n+1)} \]

Antiderivative was successfully verified.

[In]

Integrate[(c*x)^n/(a + b*x^n),x]

[Out]

(x*(c*x)^n*Hypergeometric2F1[1, 1 + n^(-1), 2 + n^(-1), -((b*x^n)/a)])/(a*(1 + n))

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fricas [F]  time = 0.62, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\left (c x\right )^{n}}{b x^{n} + a}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^n/(a+b*x^n),x, algorithm="fricas")

[Out]

integral((c*x)^n/(b*x^n + a), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (c x\right )^{n}}{b x^{n} + a}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^n/(a+b*x^n),x, algorithm="giac")

[Out]

integrate((c*x)^n/(b*x^n + a), x)

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maple [F]  time = 0.22, size = 0, normalized size = 0.00 \[ \int \frac {\left (c x \right )^{n}}{b \,x^{n}+a}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x)^n/(b*x^n+a),x)

[Out]

int((c*x)^n/(b*x^n+a),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ -a c^{n} \int \frac {1}{b^{2} x^{n} + a b}\,{d x} + \frac {c^{n} x}{b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^n/(a+b*x^n),x, algorithm="maxima")

[Out]

-a*c^n*integrate(1/(b^2*x^n + a*b), x) + c^n*x/b

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {{\left (c\,x\right )}^n}{a+b\,x^n} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x)^n/(a + b*x^n),x)

[Out]

int((c*x)^n/(a + b*x^n), x)

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sympy [C]  time = 1.22, size = 41, normalized size = 1.02 \[ - \frac {c^{n} x \Phi \left (\frac {a x^{- n} e^{i \pi }}{b}, 1, \frac {e^{i \pi }}{n}\right ) \Gamma \left (\frac {1}{n}\right )}{b n^{2} \Gamma \left (1 + \frac {1}{n}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)**n/(a+b*x**n),x)

[Out]

-c**n*x*lerchphi(a*x**(-n)*exp_polar(I*pi)/b, 1, exp_polar(I*pi)/n)*gamma(1/n)/(b*n**2*gamma(1 + 1/n))

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